60x+x^2=256

Solution for 60x+x^2=256 equation:

60x+x^2=256

We move all terms to the left:

60x+x^2-(256)=0

a = 1; b = 60; c = -256;
Δ = b2-4ac
Δ = 602-4·1·(-256)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-68}{2*1}=\frac{-128}{2}
=-64
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+68}{2*1}=\frac{8}{2}
=4
$